2 Some Remarks on Plane Curves

Work over K=KΒ―.

Definition 2.1 (Rational plane affine curve). A plane affine curve C={f(x,y)=0}βŠ‚π”Έ2 is rational if it has a rational parametrisation, i.e. βˆƒβ‘Ο•(t),ψ(t)∈K(t) such that:

  • (i) 𝔸1→𝔸2, t↦(Ο•(t),ψ(t)) is injective on 𝔸1βˆ–{finiteΒ set}.
  • (ii) f(Ο•(t),ψ(t))=0.

Example 2.2.

Remark 2.3. The genus g(C)βˆˆβ„€β‰₯0 is an invariant of a smooth projective curve C.

Proposition 2.4. Assuming that:

  • K=KΒ―

  • C a smooth projective curve

Then
  • (i) C is rational (see DefinitionΒ 2.1) if and only if g(C)=0.
  • (ii) C is an elliptic curve (see DefinitionΒ 1.5) if and only if g(C)=1.

Proof.

β–‘
Order of vanishing

C algebraic curve, function field K(C), P∈C smooth point.

We write ord⁑p(f) for the order of vanishing of f∈K(C)Γ— at P (negative of f has a pole).

Fact: ord⁑p:K(C)Γ—β†’β„€ is a discrete valuation, i.e. ord⁑p(f1f2)=ord⁑p(f1)+ord⁑p(f2) and ord⁑p(f1+f2)β‰₯min⁑(ord⁑p(f1),ord⁑p(f2)).

Definition (Uniformiser). t∈K(C)Γ— is a uniformiser at P if ord⁑p(t)=1.

Example 2.5. C={g=0}βŠ‚π”Έ2, g∈K[x,y] irreducible.

K(C)=Frac⁑K[x,y](g).

g=g0+g1(x,y)+g2(x,y)+β‹―

where gi are homogeneous of degree i.

Suppose P=(0,0)∈C is a smooth point, i.e. g0=0, g1(x,y)=αx+βy with α,β not both zero.

PIC

Fact: Ξ³x+Ξ΄y∈K(C) is a uniformiser at P if and only if Ξ±Ξ΄βˆ’Ξ²Ξ³β‰ 0.

Example 2.6.

{y2=x(xβˆ’1)(xβˆ’Ξ»)}βŠ‚π”Έ2

where Ξ»β‰ 0,1. Projective closure (x=XZ, y=YZ):

{Y2Z=X(Xβˆ’Z)(Xβˆ’Ξ»Z)}βŠ‚β„™2.

Let P=(0:1:0).

Aim: Compute ord⁑p(x) and ord⁑p(y).

Put w=ZY, t=XY. So

w=t(tβˆ’w)(tβˆ’Ξ»w)(βˆ—)

Now Pis the point (t,w)=(0,0). This is a smooth point with

ord⁑p(t)=ord⁑p(tβˆ’w)=ord⁑p(tβˆ’Ξ»w)=1.

(βˆ—) implies ord⁑p(w)=3. Therefore ord⁑p(x)=ord⁑p(tβˆ•w)=1βˆ’3=βˆ’2 and ord⁑p(y)=ord⁑p(1βˆ•w)=βˆ’3.

Riemann Roch Spaces

Let C be a smooth projective curve.

Definition (Divisor). A divisor is a formal sum of points on C, say

D=βˆ‘P∈CnpP

where npβˆˆβ„€ and np=0 for all but finitely many P∈C.

We write deg⁑D=βˆ‘nP.

We say D is effective (written Dβ‰₯0) if nPβ‰₯0 for all P.

If f∈K(C)Γ—, then div⁑(f)=βˆ‘β‘P∈Cord⁑p(f)P.

The Riemann Roch space of D∈Div⁑(C) is

L(D)={f∈K(C)Γ—|div⁑(f)+Dβ‰₯0}βˆͺ{0},

i.e. the K-vector space of rational functions on C with β€œpoles no worse than specified by D”.

We quote: Riemann Roch for genus 1:

dim⁑L(D)={ deg ⁑Dif  deg ⁑D>00 or 1if  deg ⁑D=00if  deg ⁑D<0

For example, in ExampleΒ 2.6:

L(2P)=⟨1,x⟩L(3P)=⟨1,x,y⟩

Proposition 2.7. Assuming that:

  • K=KΒ―, char⁑Kβ‰ 2

  • CβŠ‚β„™2 a smooth plane cubic

  • P∈C a point of inflection

Then we may change coordinates such that
C:Y2Z=X(Xβˆ’Z)(Xβˆ’Ξ»Z)

for some Ξ»β‰ 0,1 and P=(0:1:0).

Proof. We change coordinates such that P=(0:1:0), Tp(C)={Z=0}, and C:{F(X,Y,Z)=0}βŠ‚β„™2.

P∈C part of inflection implies F(t,1,0)=constt3, i.e. F has no terms X2Y, XY2 or Y3.

Therefore

F∈⟨Y2Z,XYZ,YZ2,X3,X2Z,XZ2,Z3⟩.

The Y2Z coefficient must be β‰ 0 otherwise P∈C is singular, and the coefficient of X3 is β‰ 0 otherwize Z|F.

We are free to rescale X, Y, Z and F. Then without loss of generality C is defined by

Y2Z+a1XYZ+a3YZ2=X3+a2XzZ+a4XZ2+a6Z3.

Weierstrass form.

Substituting Y←Yβˆ’12a1Xβˆ’12a3Z, we may suppose a1=a3=0. Now

Y2Z=Z3f(XZ)

for some monic cubic polynomial f.

C is smooth, so f has distinct roots. Without loss of generality say 0,1,Ξ». Then C is given by

Y2Z=X(Xβˆ’Z)(Xβˆ’Ξ»Z).β–‘

Remark. It may be shown that the points of inflection on a smooth plane curve

C={F(X1,X2,X3)=0}βŠ‚β„™2

are given by

F=det⁑(βˆ‚2Fβˆ‚Xiβˆ‚Xj)⏟Hessian=0,

2.1 The degree of a morphism

Let Ο•:C1β†’C2 be a non-constant morphism of smooth projective curves.

Then Ο•βˆ—:K(C2)β†’K(C1), f↦fβˆ˜Ο•.

Definition (Degree of a morphism). deg⁑ϕ[K(C1):Ο•βˆ—K(C2)].

Definition (Separable morphism). Ο• is separable if K(C1)βˆ•Ο•βˆ—K(C2) is a separable field extension.

Definition (Ramification index). Suppose P∈C1, Q∈C2, Ο•:P↦Q. Let t∈K(C2) be a uniformiser at Q.

The ramification index of Ο• at P is

eΟ•(P)=ord⁑P(Ο•βˆ—t)

(always β‰₯1, independent of choice of t).

Theorem 2.8. Assuming that:

  • Ο•:C1β†’C2 a non-constant morphism of smooth projective curves

Then
βˆ‘PβˆˆΟ•βˆ’1QeΟ•(P)= deg β‘Ο•βˆ€β‘Q∈C2.

Moreover, if Ο• is separable then eΟ•(P)=1 for all but finitely many P∈C1. In particular:

  • (i) Ο• is surjective (on KΒ―-points)
  • (ii) #Ο•βˆ’1(Q)≀deg⁑ϕ
  • (iii) If Ο• is separable then equality holds in (ii) for all but finitely many Q∈C2.

Remark 2.9. Let C be an algebraic curve. A rational map is given Cβˆ’βˆ’β†’β„™n, P↦(f0(P):f1(P):β‹―:fn(P)) where f0,f1,…,fn∈K(C) are not all zero.

Important Fact: If C is smooth then Ο• is a morphism.