7 Size Ramsey number of a graph
Definition 7.1 ( -> ).
Let ,
be
graphs. We write
to mean every red / blue colouring of
contains a monochromatic .
Example.
.
Question: How few edges can a graph
have with ?
Definition 7.2 (Size Ramsey number).
The size Ramsey number of
is
Theorem 7.3.
.
7.1 The size Ramsey number of the path
Straightforward bounds:
The upper bound is by using the bound on Ramsey numbers of sparse graphs proved last section.
Surprisingly:
Theorem 7.4 (Beck, ’83).
,
for some constant .
Theorem 7.5 (Beck, ’83 (Beck 2)).
There exists
, such that the
following holds: Let
and let .
Then
where .
Definition 7.6.
Let
be a graph on
vertices. Say that
is -pseudorandom
if all sets
which are disjoint and
have .
Lemma 7.7.
Assuming that:
Then there exists
such that if
and
then
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Proof.
For
disjoint,
Then
So done by Markov. □
Lemma 7.8.
Assuming that:
Then there exist disjoint
with ,
and
.
Proof.
We apply the following “Depth first search algorithm”. We maintain a partition
where
is a path.
First set ,
. We now repeat the
following until :
-
(1)
If ,
then move a vertex from
into .
-
(2)
If ,
let
be the end of the path .
If ,
we move
to the end of .
If ,
we move
into .
We note that since
is -free,
we have
and therefore
always.
Also note that at each step we:
Since at the start and
at the end, there must
be some time for which
and .
Now since
at all times, we are done. □
Proof of Beck, ’83 (Beck 2).
Let
be a graph on vertices
that is -pseudorandom
with . Let
, where
we choose later.
We show . So
assume not. Let
where ,
. Apply lemma
to both and
to find
with
and such that
have no red edges
between then and
have no blue edges between them.
Note
Without loss of generality assume
So
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Thus
So and
have no edges between
them in , which contradicts
the -pseudorandomness
if . So
.
So by Lemma 7.7 (which said that
is -pseudorandom
with high probability), we are done. □
Proof of Beck, ’83.
Enough to prove for
sufficiently large. We set
as before,
and let .
Then
satisfies
Now note
So (at least)
proportion of all such graphs work. □