1 The Ramsey Numbers

The course is Probabilistic Combinatorics, being lectured by

JulianSa⏟has⏟ra⏟bu⏟dhe⏟“day ″⁡

We will be studying in particular the Ramsey numbers. Starting with the simplest to define:

R(k)=min⁡{n:every red/blue colouring of E(Kn) contains a monochromatic Kn}.

Example. R(3)≤6: pick a vertex. Without loss of generality say it has at least 3 red neighbours. If any of these are connected by a red edge, then we get a red triangle by using the original vertex. If none of them are connected by a red edge, then we get a blue triangle between them.

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R(3)>5: by considering the following picture.

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Thus R(3)=6.

Main question: how fast does R(k)→∞ as k→∞?

We will also study:

R(l,k)=min⁡{n:every red/blue colouring of E(Kn) contains either a blue Kl or a red Kk}.

For a fixed graph H, we define

R(H)=min⁡{n:every red/blue colouring of E(Kn) contains a monochromatic H}.

Example. R(k)=R(Kk).

For H a fixed graph, we define

ex⁡(n,H)=max⁡{e(G):G is a graph on n vertices and G⁄⊃H}.

Example. Mantel’s Theorem says that

ex⁡(n,K3)=⌊n24⌋.

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1.1 Binomial Random Graph

Definition 1.1 (Binomial random graph). Given n∈ℕ, p∈(0,1), the binomial random graph G(n,p) is the probability space defined on all graphs on n vertices, where each edge is included independently with probability p.

1.2 Topics in this course

1.3 Brief introduction to R(k)

Theorem 1.2 (Erdos-Szekeres, ’35). R(k)≤4k.

Proof sketch. Let n≥4k and let χ be a colouring of Kn. Pick a vertex v. It must have ≥12n neighbours connected to it by the same colour.

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Now ignore everything that was connected using the other colour. Pick a new vertex from what remains, and apply the process again:

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We continue until either A or B gets to size k. We basically just want

n(12)k(12)k≥1,

i.e. n≥4k. □

How about a lower bound?

Example. The following gives R(k)≥(k−1)2+1. Quite a long way from 4k!

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Theorem 1.3 (Erdos, ’47). R(k)≥(1−o(1))k2e2k∕2.

Notation. o(1) denotes a quantity that →0 as k→∞.

Proof. Let n=(1−o(1))k2eek∕2 we choose χ to be a random colouring of E(Kn) where the colour of each edge is chosen red / blue uniformly and independently. We have

ℙ(χ has a monochromatic Kk)=ℙ(⋃K∈[n](k){K is a monochromatic clique})≤2nk2−k2≤2(enk)k2−k2=(enk2(k−12))<1

by the choice of n. □

Big question: Is there an “explicit” construction that gives R(k)≥(1+𝜀)k, for some fixed 𝜀>0?