2 Valuation Rings Definition 2 1 Valuation Let K be a field A valuation on K is a function v K such that i v x y v x v y ii v x y min v x v y Fix 0 1 If v is a valuation on K then x v x x 0 0 x 0 determines a non archimedean absolute value on K Conversely a non archimedean absolute value determines a valuation v x log x Remark Ignore the trivial valuation v x 0 Say v 1 v 2 are equivalent if there exists c 0 such that v 1 x c v 2 x for all x K Example K v p x log p x p is known as the p adic valuation If k is a field consider K k t Frac k t the rational function field Then define v t n f t g t n for f g k t with f 0 g 0 0 We call this the t adic valuation K k t Frac k t i n a i t i a i k n known as the field of formal Laurent series over k Then we can define v I a i t i min i a i 0 is the t adic valuation on K Definition 2 2 Let K be a non archimedean valued field The valuation ring of K is defined to be O K x K x 1 B 0 1 x K v x 0 0 Proposition 2 3 i O K is an open subring of K ii The subsets x K x r and x K x r for r 1 are open ideals in O K iii O K x K x 1 Proof i 0 0 1 1 so 0 1 O K If x O K then x x hence x O K If x y O K then x y max x y 1 Hence x y O K If x y O K then x y x y 1 hence x y O K Thus O K is a ring Since O K B 0 1 it is open ii Similar to i iii Note that x x 1 x x 1 1 Thus x 1 x 1 1 x x 1 O K x O K Notation m x O K x 1 is a max ideal of O K k O K m is the residue field Corollary 2 4 O K is a local ring with unique maximal ideal m a local ring is a ring with a unique maximal ideal Proof Let m be a maximal ideal Suppose m m Then there exists x m m Using part iii of Proposition 2 3 we get that x is a unit hence m O K a contradiction Example K with p Then O K p a b p b and m p p k p Definition 2 5 Let v K be a valuation If v K we say v is a discrete valuation K is said to be a discretely valued field An element O K is uniformiser if v 0 and v generates v K Example K with p adic valuation is a discrete valuation ring K k t with t adic valuation is a discrete valuation ring K k t t 1 2 t 1 4 t 1 8 Here the t adic valuation is not discrete Remark If v is a discrete valuation can replace with equivalent one such that v K Call such a v normalised valuations then v 1 if and only if is a unit Lemma 2 6 Assuming that v is a valuation on K Then the following are equivalent i v is discrete ii O K is a PID iii O K is Noetherian iv m is principal Proof i ii O K is an integral domain since it is a subset of K which is an integral domain Let I O K be a non zero ideal Let x I such that v x min v a a I which exists since v is discrete Then we claim x O K a O K v a v x is equal to I I is an ideal Let y I Then v x 1 y 0 Hence y x x 1 y x O K ii iii Clear iii iv Write m x 1 O K x n O K Without loss of generality v x 1 v x 2 v x n Then x 2 x n x 1 O K Hence m x 1 O K iv i Let m O K for some O K and let c v Then if v x 0 x m hence v x c Thus v K 0 c Since v K is a subgroup of we deduce v K Suppose v is a discrete valuation on K O K a uniformiser For x K let n such that v x n v Then u n x O K and x u n In particular K O K 1 and hence K Frac O K Definition 2 7 Discrete valuation ring A ring R is called a discrete valuation ring DVR if it is a PID with exactly one non zero prime ideal necessarily maximal Lemma 2 8 i Let v be a discrete valuation on K Then O K is a discrete valuation ring ii Let R be a discrete valuation ring Then there exists a valuation on K Frac R such that R O K Proof i O K is a PID by Lemma 2 6 Hence any non zero prime ideal is maximal and hence O K is a discrete valuation ring since it is a local ring ii Let R be a discrete valuation ring with maximal ideal m Then m for some R Since PIDs are UFDs we may write any x R 0 uniquely as n u with n 0 u R Then any y K can be written uniquely as m u with u R m Define v m u m check v is a valuation and O K R Example p k t k a field are discrete valuation rings