Lemma 9.1.
Assuming that:
E
∕
K
have
integral
Weierstrass equation
y
2
+
a
1
x
y
+
a
3
y
=
x
3
+
a
2
x
2
+
a
4
x
+
a
6
0
≠
P
=
(
x
,
y
)
∈
E
(
K
)
Then
either
x
,
y
∈
O
K
or
{
v
(
x
)
=
−
2
s
v
(
y
)
=
−
3
s
for some
s
≥
1
.